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User:GiverOfThePeace/Kai Splits Mountain: Difference between revisions
 GiverOfThePeace (talk | contribs) (Created page with "==Kai Splits a Mountain== 350px [https://www.youtube.com/watch?v=-qqGtIukIYQ&t=43s In this scene], Kai slams into the ground so hard, it splits the mountain behind it. [https://web.archive.org/web/20160412093546/http://www.dreamworks.com/kungfupanda/characters/po Po is 6'2" or 1.8796 m] . In the image, Po is about 371 px while Oogway is about 350 px. (1.8796/371)*350=1.77320754717 m 350px Now, in this image, ass...") |
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Latest revision as of 14:16, 9 February 2024
Kai Splits a Mountain
In this scene, Kai slams into the ground so hard, it splits the mountain behind it. Po is 6'2" or 1.8796 m . In the image, Po is about 371 px while Oogway is about 350 px.
(1.8796/371)*350=1.77320754717 m
Now, in this image, assuming the main portion of the glowing trail is Oogway, that would mean he's about 23 px while the length of the mountain is about 886 px.
(1.77320754717/23)*886=68.3070385562 m
I'll be using shear force to find how much energy he'd need to split the mountain usin shear force. Using the area of a circle, we get a surface area of:
pi*34.1535192781^2=3664.5512116 m^2
The average MPa of rock is 60 MPa or 60000000 n/m^2. The value to change shear force to tensile is 0.6.
3664.5512116*60000000*.6=131923843618 N
Multiplying it by the diameter now, we get:
131923843618*68.3070385562=9.0113271e+12 J (City District level)
