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User:GiverOfThePeace/The Moon Didn't Deserve This: Difference between revisions
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== Introduction == | == Introduction == | ||
The following calculation is taken from [https://docs.google.com/document/d/1KJaPykfP6XsvDT-NaU9m3NCnUPh_3LXomuws5vgygYY/edit this google document] (With adjustments made for our | The following calculation is taken from [https://docs.google.com/document/d/1KJaPykfP6XsvDT-NaU9m3NCnUPh_3LXomuws5vgygYY/edit this google document] (With adjustments made for our current standards. The Kinetic Energy portion isn't used as it does not meet our [https://discordapp.com/channels/797643814138544188/851962308833181757/1059215981714608198 Kinetic Energy standards]. | ||
== The Calculation == | == The Calculation == | ||
=== Calculating the Explosion === | === Calculating the Explosion === | ||
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Volume of a Cylinder = 8.33e+12g^3 or '''8.33e+24cm^3''' | Volume of a Cylinder = 8.33e+12g^3 or '''8.33e+24cm^3''' | ||
8.33e+24*[https://thecodex. | 8.33e+24*[https://thecodex.wiki/wiki/User:MrWarnerTheGreat/Sandbox9#Basalt 1.2] = '''9.996e+24 Joules''', or about '''2389.1013 teratons of TNT''' (High 6-B). | ||
== Conclusion == | == Conclusion == | ||
Latest revision as of 16:04, 9 February 2024
Introduction
The following calculation is taken from this google document (With adjustments made for our current standards. The Kinetic Energy portion isn't used as it does not meet our Kinetic Energy standards.
The Calculation
Calculating the Explosion
Kirby’s Adventure/Nightmare in Dreamland’s Moon Explosion It’s important to note that the size of the hole left in the moon varies from game to game, mostly with the size being larger than how it's depicted here. That said, it’s probably for the best to just assume that the high is the most likely answer (Especially given how future Kirby games ramp up in feats)
Diameter of the Moon (380 px) = 3474km
Radius of the explosion (149.9px) = 1370401.57895
1370401.57895^3*((27136*1.37895+8649)^(1/2)/13568-93/13568)^2 = 8.654076816e+23 joules, or 2.068374e+14 tons of TNT (206.83740000000000236 teratons of TNT), 6-B.
Calculating the Fracture Strength
Diameter of the Crater (185.3 px) = 1746.8km
Radius of the Crater = 873.4km
Volume of a Cylinder = 8.33e+12g^3 or 8.33e+24cm^3
8.33e+24*1.2 = 9.996e+24 Joules, or about 2389.1013 teratons of TNT (High 6-B).
Conclusion
Explosion itself: 206.83740000000000236 teratons of TNT (6-B)
Destroying a hole in the moon: 2389.1013 teratons of TNT (High 6-B)
