User:GiverOfThePeace/Official Blog Explaining the Reasonings for our Attack Potency Borders

I’ve noticed that our borders for the attack potency tier don’t really have a justification for most of the values, I guess I’ll get to fixing that. For note each baseline value for the system past wall level is essentially assuming the object being engulfed by an omnidirectional explosion.

This is the calculator I’ll be using for KE so I don’t need to keep repeating the formula.

This is the calculator I'll use for math.

Below Average Human level

This one will basically be starting at 0 joules and moving to what the baseline of human levels joules are, which is 50 joules.

Human level

This will be used assuming the kinetic energy exerted from the average humans punch.

The average human weighs 62 kg.

Total body weight percentage for an arm is 5.335%.

The average punching speech for an untrained martial arts is 15 mph

62 kg * 5.335% = 3.3077 kg

KE = ½(3.3077kg)(6.7056m/s) = 74.37 Joules or 75.

Athlete level

According to this site athletes can range from 139 joules to 160 joules, so the baseline here should be about 130 joules.

Peak Human

This is gonna be the changed name of Street level since the name of the level itself is misleading and denotes the idea of someone destroying a street when it’s really for characters with peak human to low superhuman statistics. The joule count for this starts at 300 as most bullets and top experts reach around 400 joules and higher.

Wall level

It has been shown that a .50 BMG Round can puncture a brick wall which at it’s lowest deals about 14000 joules.

Room level

It was agreed upon that “Small Building level” being 9-A doesn’t make sense when all of the other “small” level terms are all under the same tier with just a “Low” or “High” to replace them. Thus “Small Building level” has been renamed to “Room level” with Small Building level becoming Low 8-C.

Room level’s baseline according to this site, the average dimensions for a living room is 16 x 20, but to make it into a regular average we'll change it to a perfect 20 x 20 which would make it 400 square feet and 20 feet. Using this, the formula would be

W = (6.096m)^3*((27136*1.37895+8649)^(1/2)/13568-93/13568)^2

W = 0.018206245316128095 Tons of TNT or 7.617493040267995e7 Joules.

Small Building level

As said with Room level, Small Building level is now Low 8-C.

Small Building's baseline is based off this site which says the average square footage of a house is 2,273 square feet, or 47.68 feet/14.532864 meters.

W = (14.532864m)^3*((27136*1.37895+8649)^(1/2)/13568-93/13568)^2

W = 0.246682955723737567076139949247515 tons of TNT, rounding up this gets .25 tons of TNT or 1.046e+9 Joules.

Building level

It's noted here that the average square foot for a building in the 2000s is 19,000 square feet.

W = (42.00144m)^3*((27136*1.37895+8649)^(1/2)/13568-93/13568)^2

W = 5.9549491310924577933887114452 Tons of TNT, we'll round this one down to 5 tons of TNT or 2.092e+10 Joules to mix together with Large Building and City Block's ranges.

Large Building level

Initially skyscrapers were accepted as the high end of Large Building but after calculating the destruction of a skyscraper, it got into far higher ranges, so it cannot be used at all. Large Building will be the in-between of Building and City Block, 7.5 tons as a baseline and 10 tons as the end due to City Block level.

City Block level

A city block’s standard size is 100m x 200m.

We’ll use 200 end since that’s dealing with length. 50^3*((27136*1.37895+8649)^(1/2)/13568-93/13568)^2 = 10.0460544623238495 tons of TNT or 10 Tons of TNT.

City District level

The assumed baseline is 100 tons as there’s no real valid way to calc it other then finding an unlikely distance between 2 city blocks.

Town level

Small and Large Town modifiers were deemed ultimately pointless since a town by definition is an area that is larger then a village but smaller then a city. So Large Town and Town are merged together while City District level and Small Town are merged together.

Town level’s baseline has been put as 10 kilotons. As fatman is rated about 21 kilotons.

City level

Small City like Small and Large Town modifiers were deemed ultimately pointless and since there is no Large City modifier, the only real thing needed is to merge city and small city.

1 megaton of TNT. As a single megaton is considered nuclear weapon levels.

Mountain level

Large Mountain and Mountain have the same thing as city.

So since fragmentation is 10^17 joules, for round sakes we'll put the baseline of mountain at 100 megatons of TNT.

We find the rounded baseline for this and Island through finding different scales for what’s considered a legitimate mountain/island or not.

• Fragmentation: Mountain level
  • (4.184e17 Joules) / (8 Joules/cc) = 5.230e16 cm^3, or 5.230e10 m^3 destroyed.

Assuming that a mountain is considered a cone, the volume for that is **(Pi)*(Radius^2)*(Height/3)

• • Assuming that the mountain's height and radius are equal, the minimum values for both radius and height should be about 3682.55m.
  • Plug the above number for both radius and height for the cone volume and you get the volume required for Mountain level via fragmenting it.
• Violent Fragmentation: Mountain level
  • (4.184e17 Joules) / (69 Joules/cc) = 6.064e15 cm^3, or 6.064e9 m^3 destroyed.
  • Assuming that a mountain is considered a cone, the volume for that is **(Pi)*(Radius^2)*(Height/3)
  • Assuming that the mountain's height and radius are equal, the minimum values for both radius and height should be about 1795.72m.
  • Plug the above number for both radius and height for the cone volume and you get the volume required for Mountain level via violent fragmentation.
• Pulverization: Mountain level
  • (4.184e17 Joules) / (214 Joules/cc) = 1.955e15 cm^3, or 1.955e9 m^3 destroyed.
  • Assuming that a mountain is considered a cone, the volume for that is **(Pi)*(Radius^2)*(Height/3)
  • Assuming that the mountain's height and radius are equal, the minimum values for both radius and height should be about 1231.33m.
  • Plug the above number for both radius and height for the cone volume and you get the volume required for Mountain level via pulverization.
• Vaporization: Mountain level
  • (4.184e17 Joules) / (25700 Joules/cc) = 1.547e13 cm^3, or 1.547e7 m^3 destroyed.
  • Assuming that a mountain is considered a cone, the volume for that is **(Pi)*(Radius^2)*(Height/3)
  • Assuming that the mountain's height and radius are equal, the minimum values for both radius and height should be about 249.16m.
  • Plug the above number for both radius and height for the cone volume and you get the volume required for Mountain level via vaporization.

Island level

Same thing for Mountain will be done for Island, as Large Island modifier has the same issue.

For the sake of rounding again, we'll put the baseline of Island at 1 gigaton of TNT.

• Fragmentation: Island level
  • (1.8e19 Joules) / (8 Joules/cc) = 2.250e18 cm^3, or 2.25e12 m^3 destroyed.
  • Mean/Average height of land elevation above sea level is 840m
  • Volume of rectangle = Length*Width*Height, where Height = 840m
  • Volume of cylinder = (Pi)*(Radius^2)*(Height), where Height = 840m
  • Isolate for both Length and Width, assuming that both are equal, and you get a value of 51755m for length and width of said island respectively.
  • If the island is Rectangular:
    • The dimensions of said island would have to be 51755m x 51755m x 840m to yield ***Island level values fragmenting it.

• • If the island is Cylindrical, the dimensions of said island would have to be:
    • Radius = 29200m
    • Height = 840m
    • in order to yield Island level values fragmenting it.

• Violent Fragmentaton: Island level
  • (1.8e19 Joules) / (69 Joules/cc) = 2.61e17 cm^3, or 2.61e11 m^3 destroyed.
  • Mean/Average height of land elevation above sea level is 840m
  • Volume of rectangle = Length*Width*Height, where Height = 840m
  • Volume of cylinder = (Pi)*(Radius^2)*(Height)
  • Isolate for both Length and Width, assuming that both are equal, and you get a value of 5574m for length and width of said island respectively.

• • If the island is Rectangular:
    • The dimensions of said island would have to be 17627m x 17627m x 840m to yield ***Island level value via violent fragmentation.

• • If the island is Cylindrical, the dimensions of said island would have to be:
    • Radius = 9945m
    • Height = 840m
    • in order to yield Island level values via violent fragmentation.

• • Pulverization: Island level
    • (1.8e19 Joules) / (214 Joules/cc) = 8.411e16 cm^3, or 8.411e10 m^3 destroyed.
    • Mean/Average height of land elevation above sea level is 840m
    • Volume of rectangle = Length*Width*Height, where Height = 840m
    • Volume of cylinder = (Pi)*(Radius^2)*(Height)
    • Isolate for both Length and Width, assuming that both are equal, and you get a value of 5574m for length and width of said island respectively.

• • If the island is Rectangular:
    • The dimensions of said island would have to be 10007m x 10007m x 840m to yield ***Island level value via violent fragmentation.
    • If the island is Cylindrical, the dimensions of said island would have to be:

• • • Radius = 5654m
    • Height = 840m
    • in order to yield Island level values via pulverization.

• • Vaporization: Island level
    • (1.8e19 Joules) / (27050 Joules/cc) = 6.654e14 cm^3, or 6.654e8 m^3 destroyed.
    • Mean/Average height of land elevation above sea level is 840m
    • Volume of rectangle = Length*Width*Height, where Height = 840m
    • Volume of cylinder = (Pi)*(Radius^2)*(Height)
    • Isolate for both Length and Width, assuming that both are equal, and you get a value of 5574m for length and width of said island respectively.

• • If the island is Rectangular:
    • The dimensions of said island would have to be 17627m x 17627m x 840m to yield

• Island level value via vaporization.
  • If the island is Cylindrical, the dimensions of said island would have to be:
    • Radius = 9945m
    • Height = 840m
    • in order to yield Island level values via violent fragmentation.

• Pulverization: Island level
  • (1.8e19 Joules) / (214 Joules/cc) = 8.411e16 cm^3, or 8.411e10 m^3 destroyed.
  • Mean/Average height of land elevation above sea level is 840m
  • Volume of rectangle = Length*Width*Height, where Height = 840m
  • Volume of cylinder = (Pi)*(Radius^2)*(Height)
  • Isolate for both Length and Width, assuming that both are equal, and you get a value of 5574m for length and width of said island respectively.

• • If the island is Rectangular:
    • The dimensions of said island would have to be 10007m x 10007m x 840m to yield ***Island level value via violent fragmentation.

• • If the island is Cylindrical, the dimensions of said island would have to be:
    • Radius = 5654m
    • Height = 840m
    • in order to yield Island level values via pulverization.

• Vaporization: Island level
  • (1.8e19 Joules) / (27050 Joules/cc) = 6.654e14 cm^3, or 6.654e8 m^3 destroyed.
  • Mean/Average height of land elevation above sea level is 840m
  • Volume of rectangle = Length*Width*Height, where Height = 840m
  • Volume of cylinder = (Pi)*(Radius^2)*(Height)
  • Isolate for both Length and Width, assuming that both are equal, and you get a value of 5574m for length and width of said island respectively.

• • If the island is Rectangular:
    • The dimensions of said island would have to be 17627m x 17627m x 840m to yield Island level value via vaporization.

Small Country level

The baseline modifier for Small Country will be 1 teraton as a teraton is a powerful energy equivalent to a magnitude an 11.2 richter earthquake.

The end scale will be 10 teratons as the largest smallest country according to this site is Greece.

Greece has a length of 940 kilometers.

Thus via radius it is 470 km and 470000 meters.

470000^3*((27136*1.37895+8649)^(1/2)/13568-93/13568)^2 = 8344092099534.7922162370927461 tons of TNT or 8.3440920995347909184 Teratons of TNT. Thus the higher border of Small Country with the largest Small Country, Greece, is 8 teratons. We shall put the end border at 10 teratons.

Country level

Country starts at 10 Teratons of TNT, it will go to 500 teratons as the end for Large Country to have a 500 teraton to 1 petaton difference.

Large Country level

As stated with country, the baseline will be 500 teratons to 1 petaton.

Continent level

United states will be used as a baseline, which is 3000 miles wide.

2,414,016^3*((27136*1.37895+8649)^(1/2)/13568-93/13568)^2 = 1.1305921039356015881e15 or 1.1305921039356015001 petatons of TNT.

Rounding down, Continent level will start at 1 petaton.

Multi-Continent level

So the baseline for Multi-Continent level would be the distance between two furthest points on earth.

The furthest that two places could be apart would be 12,430 miles or 20,004 km. apart.

Ground Explosion: W = 10002000^3*((27136*1.37895+8649)^(1/2)/13568-93/13568)^2 = 8.0416666404865181824e16 tons of tnt or 80.416666404865182471 petatons of TNT.

Air Explosion: Y = ((10002/0.28)^3)/1000 = 45581273688.411079407 megatons of TNT or 45.581273688411080514 petatons of TNT. The lower border will be used here, which is 45 petatons and round it down to 40 petatons of TNT.

Moon level

The gravitational binding energy of the moon is 1.2 x 10^29 joules. Thus it is the baseline.

Small Planet level

For small planet the default assumption is Mecury.

The GBE of Mercury is 1.8×10^30 joules.

Planet level

The gravitational binding energy of Earth is about 2x10^32 joules.

Large Planet level

Using this site, I found Neptune's GBE, which is a good baseline for Large Planet level. Neptune got 1.705e34 Joules.

Brown Dwarf level

Brown Dwarves are personally distinct enough to warrant their own tier. They are a true in-between where they are too massive to be considered planets, but they don't sustain nuclear fusion like normal stars.

A brown dwarf has a polytropic value of 1.5. https://debatesjungle.fandom.com/wiki/How_to_Handle_Calculations#Gravitational_Binding_Energy

Brown dwarves start at ~13x Jupiter masses and go up to 80x Jupiter masses. https://www.caltech.edu/about/news/bands-clouds-swirl-across-brown-dwarfs-surface

They can vary between 0.64-1.13 RJ (Jupiter Radius). https://arxiv.org/abs/1304.1259

U = (3×G×(M^2))/(r(5-n))

G = 6.67408x10^-11

N = 1.5

Low end

M = 13 Jupiter Masses/2.47E+28kg

R = 4.5755e+7m

Plugging in values...

U = 7.6278117e+38 Joules

High end

M = 80 Jupiter Masses/1.52E+29kg

R = 8.0786e+7m

Plugging in values...

U = 1.6360467e+40 Joules

Low Mass Star level

The baseline for it is the end value of brown dwarf level.

Star level

The gravitational binding energy of the sun is 2.3 x 10^41 Joules.

High Mass Star level

The Large Star level name has been changed to Massive Star level due to it being the more accurate name. To briefly explain, a star does not get a higher GBE via its size but it’s solar mass. So a star that’s visually smaller could actually have a greater GBE then a star that’s visually larger. Due to this, Massive Star level was decided as the better naming convention as it covers the more scientifically accurate approach to stars.

Rigel A is used for Massive Star level’s baseline.

The GBE formula is U = (3GM^2)/r(5-n)

(3*(6.67408×10^-11)*((1.989×10^30)*23)^2)/(((6.957×10^8)*78.9)*(5 - 3)) = 3.817x10^42 Joules

Solar System level

The baseline for Solar System level will be 10^44 joules as a supernova is the event that helped determine the composition of the Solar System 4.5 billion years ago, and may even have triggered the formation of this system.

Multi-Solar System level

For this, I’m using the Proxima Centauri b, an object in another solar system with the lowest distance, 4.2 light-years or 4.0×10^13 km.

W = Radius is meters^3*((27136*P+8649)^(1/2)/13568-93/13568)^2 Ground Explosion is W = 2e16^3*((27136*1.37895+8649)^(1/2)/13568-93/13568)^2

Which gives 2.69009227970323083e+54 Joules

Air Explosion is Y = ((4e13/0.28)^3)/1000

Which gives 1.21982507288629738e+55 Joules Seeing as air explosion is more likely, the air explosion end will be used.

Star Cluster level

For this, I will use the standard Star Cluster, which vary from 10 lightyears to 30 lightyears.

Obviously we'll use 10 lightyears.

W = Radius is meters^3*((27136*P+8649)^(1/2)/13568-93/13568)^2 Ground Explosion is W = 1.419e17^3*((27136*1.37895+8649)^(1/2)/13568-93/13568)^2

Which gives 9.60780936781443025e+56 Joules

Air Explosion is Y = ((2.838e+14/0.28)^3)/1000

Which gives 4.3566709033731776e+57 Joules

As usual, air explosion end will be used.

Multi-Star Cluster level

This end is based off the largest globular star cluster in the milky way, Omega Centauri, which is 230 lightyears in size. W = Radius is meters^3*((27136*P+8649)^(1/2)/13568-93/13568)^2 Ground Explosion is W = 1.088e18^3*((27136*1.37895+8649)^(1/2)/13568-93/13568)^2

Which gives 4.33075760994122948e+59 Joules

Air Explosion is Y = ((2.176e+15/0.28)^3)/1000

Which gives 1.96378643106705542e+60 Joules

As usual, air explosion end will be used.

Galaxy level

The milky way has a diameter of 100,000 light years.

W = Radius is meters^3*((27136*P+8649)^(1/2)/13568-93/13568)^2 Ground Explosion is W =(4.73037e+17)^3^3((27136*1.37895+8649)^(1/2)/13568-93/13568)^2

Which gives 3.55928304850179167e+58 Joules

Air Explosion is Y = ((9.46073e+17/0.28)^3)/1000

Which gives 1.6139553907864126e+68 Joules

Now because the ground explosion value is ridiculously lower and causes a really small gap between Multi-Solar System and Galaxy, and to add on, an omnidirectional explosion of a galaxy would in most cases be an air explosion, we’ll use that end.

Multi-Galaxy level

Distance between two galaxies is about one million light years.

So 4.730365e18 km or 4.7303650000000002e21 meters

Ground Explosion is

W = 4.7303650000000002e21^3((27136*1.37895+8649)^(1/2)/13568-93/13568)^2= 8.5068636759790525831e60 Tons of TNT or 3.5592717620296359e70 Joules

Air Explosion is Y = ((9.46073e18km/0.28)^3)/1000 = 3.8574459626826303617e55 Megatons of TNT or 1.6139553907864124e71 Joules Same thing as the above, air explosion end will be used.

Galaxy Cluster level

Based on the size of the Virgo Cluster, which is the cluster our galaxy is a part of.

15,000,000 lightyears

Air Explosion is

Y = ((1.41910957e20km/0.28)^3)/1000 = 1.3018882050589469621e59 Megatons of TNT or 5.44710024996663383e+74 Joules

Supercluster level

Based off of the Virgo Supercluster, which the Virgo Cluster and subsequently our galaxy are a part of.

110,000,000 lightyears

Air Explosion is

Y = ((1.040680352e21/0.28)^3)/1000 = 5.1342613459662606035e61 Megatons of TNT or 2.14817494715228329e77 Joules

Multi Supercluster level

Superclusters tend to be hundreds of millions of lightyears away from each other, with a source giving us 55 megaparsecs as an average, which is equivalent to 179,386,008 light years. Assuming both superclusters are the size of the virgo supercluster, the combined distance would be about 400,000,000 lightyears. Another way to set the bar for the tier is 1,200,000,000 lightyears, as it is the theoretical size limit for cosmic structures as predicted by the cosmological principle (although there are observed structures that seem to surpass this). Due to this, we'll be using the 1.2 billion lightyears end. The high end for this tier is infinite space. The source for distance is here.

Air Explosion is

Y = ((1.1352876567e22/0.28)^3)/1000 = 6.6656676222316368516e64 Megatons of TNT or 2.78891533314171681e80 Joules